You're checking for a null local variable value in the third conditional, but appending to that same variable in the first two, which would either cause a runtime error in most languages or never pass the third conditional.
In Ruby, for example, you could append a string to nil by interpolating the nil into a string literal, or various other ways. Seeing as he didn't specify the language, what the variable was initialized to, or what exactly "append" means, we can only assume that these imaginary things behave as intended.
This is my conclusion as well. To wit, an approximate translation of his method into Ruby:
fizzbuzz = (1..100).to_a.map do |i|
result = "" # 1:23 initialize a variable
result += "Fizz" if i % 3 == 0
result += "Buzz" if i % 5 == 0
result = i.to_s if result.nil?
result
end
The corrected solution would be to change `result.nil?` to `result.empty?`, i.e. checking for "empty string" instead of "null".
Well, that would depend on the print statement. Generally, all of them have new lines. Even if they don't you would have to generate new lines appropriately otherwise the next number would print right next to Fizz.
PS : My assumption is that you need to print each number or Fizz or Buzz or FizzBuzz in a separate line.
